Minimum Number of Arrows to Burst Balloons

Category
Intervals
Checkbox
Checkbox
Difficulty
Medium
Index
73
Key Ideas
The key idea to solve this problem is to sort the intervals based on their end points and then use a greedy approach to find the minimum number of arrows needed to burst all the balloons.
Problem Number
452
Problem Summary
The problem "Minimum Number of Arrows to Burst Balloons" (Problem Number: 452) is a medium-level problem in the Intervals category on LeetCode. The goal is to find the minimum number of arrows needed to burst a set of balloons, where each balloon is represented by an interval on a number line. A key pitfall in this problem is to correctly identify the overlapping intervals and efficiently determine the minimum number of arrows needed to burst all the balloons.
Solution Summary
The best solution to solve the Minimum Number of Arrows to Burst Balloons problem is as follows: 1. Sort the balloons by their end points in ascending order. 2. Initialize a variable end to the first balloon's end point. 3. Iterate through the remaining balloons. 4. If the current balloon's start point is greater than end, it means a new arrow is needed. Increment the arrow count and update end to the current balloon's end point. 5. If the current balloon's start point is less than or equal to end, it means the arrow can burst this balloon without a new arrow. Update end to the minimum of end and the current balloon's end point. 6. Repeat steps 4 and 5 until all balloons are processed. 7. Return the total number of arrows used. This solution works by greedily bursting the balloons using the minimum number of arrows. By sorting the balloons based on their end points, we can easily determine if a new arrow is needed or if an existing arrow can be used to burst multiple balloons.
Tags
Array
Greedy
Sorting